Ask Question
17 June, 14:35

A current of I = 3.8 A is passing through a conductor with cross sectional area A = 2.5 x 10^-4 m^2. The charge carriers in the conductor, electrons, have a number density n = 1.3 x 10^27 m^-3.

(a) Express the drift velocity of electrons through 1. A. n, and the fundamental charge e.

(b) Calculate the numerical value of v, in m/s.

+4
Answers (1)
  1. 17 June, 14:37
    0
    current, i = 3.8 A

    Area of crossection, A = 2.5 x 10^-4 m²

    number density, n = 1.3 x 10^27 m^-3

    (a) the relation between the current and the drift velocity is given by

    i = n e A v

    where, e is the electronic charge, A be the area of crossection area of the wire and v be the drift velocity

    v = i / neA

    (b)

    3.8 = 1.3 x 10^27 x 1.6 x 10^-19 x 2.5 x 10^-4 x v

    3.8 = 52000 v

    v = 7.3 x 10^-5 m/s
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “A current of I = 3.8 A is passing through a conductor with cross sectional area A = 2.5 x 10^-4 m^2. The charge carriers in the conductor, ...” in 📗 Physics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers