Ask Question
8 May, 06:12

A 0.250 kg fan cart accelerates at 24 cm / s^2 for 4.5 seconds. what is the net force (fan thrust minus drag and friction) on the cart? How fast will it be going at the end of the 4.5 seconds?

+3
Answers (1)
  1. 8 May, 06:26
    0
    0.06 N

    1.08 m/s

    Explanation:

    m = mass of the fan cart = 0.250 kg

    a = acceleration of the fan cart = 24 cm/s² = 0.24 m/s²

    F = Net force on the cart

    Net force on the cart is given as

    F = ma

    F = (0.250) (0.24)

    F = 0.06 N

    v₀ = initial velocity of the cart = 0 m/s

    v = final velocity of the cart

    t = time interval = 4.5 s

    Using the equation

    v = v₀ + a t

    v = 0 + (0.24) (4.5)

    v = 1.08 m/s
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “A 0.250 kg fan cart accelerates at 24 cm / s^2 for 4.5 seconds. what is the net force (fan thrust minus drag and friction) on the cart? How ...” in 📗 Physics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers