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28 September, 05:00

The force between a pair of. 005 charges is 750 N. What is the distance between them?

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  1. 28 September, 05:05
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    Question: The force between a pair of 0.005 C is 750 N. What is the distance between them?

    Answer:

    17.32 m

    Explanation:

    From coulomb's Law,

    F = kqq'/r² ... Equation 1

    Where F = Force between the force, q' and q = both charges respectively, k = coulomb's constant, r = distance between both charges.

    make r the subject of the equation above

    r = √ (kqq'/F) ... Equation 2

    From the question,

    Given: q = q' = 0.005 C, F = 750 N

    Constant: k = 9.0*10⁹ Nm²/C².

    Substitute these values into equation 2

    r = √ (9.0*10⁹*0.005*0.005/750)

    r = √ (300)

    r = 17.32 m.

    Hence the distance between the pair of charges = 17.32 m
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