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21 February, 14:43

A motorist inflates the tires of her car to a pressure of 180 kPa on a day when the temperature is - 8.0° C. When she arrives at her destination, the tire pressure has increased to 245 kPa. What is the temperature of the tires if we assume that the tires do not expand?

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  1. 21 February, 14:58
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    Apply Gay-Lussac's law:

    P/T = const.

    P = pressure, T = temperature, the quotient of P/T must stay constant.

    Initial P and T values:

    P = 180kPa, T = - 8.0°C = 265.15K

    Final P and T values:

    P = 245kPa, T = ?

    Set the initial and final P/T values equal to each other and solve for the final T:

    180/265.15 = 245/T

    T = 361K
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