Ask Question
4 April, 16:16

It is well known that bullets and other missiles fired at Superman simply bounce off his chest. Suppose that a gangster sprays Superman's chest with 6.7 g bullets at the rate of 78 bullets/min, and the speed of each bullet is 530 m/s. Suppose too that the bullets rebound straight back with no change in speed. What is the magnitude of the average force on Superman's chest from the stream of bullets?

+1
Answers (1)
  1. 4 April, 16:42
    0
    Answer: 9.2 N

    Explanation:

    Δt = 1min/78 = 60/78 = 0.77s

    
FΔt=Δp = mΔv = m[v - (-v) ] = 2mv

    
F=2mv/Δt

    = 2 x 0.0067x 530/0.77 = 0.0134 x 688.31 = 9.2 N
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “It is well known that bullets and other missiles fired at Superman simply bounce off his chest. Suppose that a gangster sprays Superman's ...” in 📗 Physics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers