A 50 g ice cube can slide without friction up and down a 30â slope. the ice cube is pressed against a spring at the bottom of the slope, compressing the spring 10 cm. the spring constant is 25 n/m. when the ice cube is released, what total distance will it travel up the slope before reversing direction?

Fk = mgcostheta * coefficient of friction

Fk = (.05kg) (9.80) (cos30) (.20) =.085 N

change in thermal energy = Fk * distance covered up slope (d)

change in thermal energy =.085 * d

the final height so y=dsin30

Kf + Uf + change in thermal energy = Ki + Ui

(.05kg) (9.80) (dsin30) + (.085d) = (.5) (25 N/m) (.1m) ^2

d =.379 m = 37.9 cm