100j of heat energy are transferred to 80 g of mercury. By how much does the temperature increase?

Given: Heat given to mercury (Q) = 100 J

Mass of mercury (m) = 80 g = 80 * 10⁻³ kg

Specific Heat capacity of mercury (c) = 138 J/kg°C

Let the rise of temperature be Δt

Formula Used: Q = mcΔt

Here, all alphabets are in their usual meanings.

Calculation:

Q = mcΔt

or, Δt = Q / mc

or, Δt = 100 J / [ (80 * 10⁻³ kg) * (138 J/kg°C) ]

or, Δt = 9.058 °C

or, Δt = 9.1 °C

Hence, the required increase in temperature will be 9.1 °C.