Why would Sodium (Na) and Chlorine (CI) want to form a lonic Bond?

-to achieve a full inner valence shell

-to achieve a equal amount of protons & electrons in their nucleus

-to achieve an stable amount of protons & neutrons in their nucleus

-to achieve a stable octet of electrons in their outer shell

Answer: to achieve a stable octet of electrons in their outer shell

Explanation:

- Sodium (Na) has an atomic number of 11, and an electronic configuration of 1s2, 2s2 2p6, 3s1.

- Chlorine (CI) Sodium (Na) has an atomic number of 17, and an electronic configuration of 1s2, 2s2 2p6, 3s2 3p5.

Hence, sodium donates its single valence electron to chlorine, thereby achieving a stable octet structure of 1s2, 2s2 2p6 while chlorine accept the single electron also forming a stable octet structure of 1s2, 2s2 2p6, 3s2 3p6. Therefore, the reaction yields NaCl, an ionic compound with ionic (electrovalent) bond.

Na + Cl - -> NaCl

Thus, Sodium (Na) and Chlorine (CI) want to form a lonic Bond because both acheive a completely filled outermost shell (octet structure)