An object with mass 110 kg moved in outer space. When it was at location its speed was 19.5 m/s. A single constant force N acted on the object while the object moved to location m. What is the speed of the object at this final location

v = 21.4m/s

Explanation:

Given r1 = m,

F = N, r2 = m

Where r1 and r2 are position vectors in space and F is the constant force vector in space.

r2 - r1 = m

Δr = m

F = m*a

a = F/m

m = 110kg (scalar quantity)

a =

a = m/s²

Since the force is constant, the acceleration is also constant. Therefore the equations of constant acceleration motion apply here.

V² = u² + 2aΔr

The magnitude of the acceleration is calculated as follows

a = √ (2.27² + 3.55² + (-2) ²)

a = √ (21.7554)

a = 4.66m/s²

Magnitude of Δr,

Δr = √ (6² + (-5) ² + (-3) ²) = √ (70) = 8.37m

Having calculated the magnitude of the acceleration and displacement, we can now calculate the final velocity.

u = initial velocity = 19.5m/s

v² = 19.5² + 2*4.66*8.37

v² = 458.25

v = √ (458.25)

v = 21.4m/s