A patio swing is suspended by two springs, each of which has a force constant of 450 N/m equivalent to a single spring forest constant of 900 N/m. Find the mass of a person sitting on the swing oscillating up and down out of 0.560 Hz.

Question

Aidyn Morrow

Physics

4 October, 09:18

A patio swing is suspended by two springs, each of which has a force constant of 450 N/m equivalent to a single spring forest constant of 900 N/m. Find the mass of a person sitting on the swing oscillating up and down out of 0.560 Hz.

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Answers (1)

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Jair · Answer 1

Frequency of a spring is:

2πf = √ (k/m)

Solving for m:

(2πf) ² = k / m

m = k / (2πf) ²

Plugging in values:

m = (900 N/m) / (2π (0.560 Hz)) ²

m = 72.7 kg

Round as needed.