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5 December, 15:04

An automobile is depreciating at 11% per year, every year. A $30,000 car depreciating at this rate can be modeled by the equation V (t) = 30,000 (0.89) t. What is an equivalent equation for this vehicle at a daily depreciation and what is it worth (rounded to the nearest thousand dollar) 5 years after purchase?

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  1. 5 December, 15:14
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    a. V (t/365) = 30,000 (0.89) ^ (t/365).

    b. V (5) = $17000

    Explanation:

    An automobile is depreciating at 11% per year, every year. A $30,000 car depreciating at this rate can be modeled by the equation V (t) = 30,000 (0.89) t. What is an equivalent equation for this vehicle at a daily depreciation and what is it worth (rounded to the nearest thousand dollar) 5 years after purchase?

    i will like to work back from te question by solving questin 2 first

    V (t) = 30,000 (0.89) ^t

    let t=5

    V (5) = 30,000 (0.89) ^5

    V (5) = $17000

    2. yearly depreciation will be

    30,000 (0.89) ^1

    26700=it amounts to tis after a year,

    so it depreciates by 3300 for one year

    daily depreciation will be 3300/365,

    since there are 365 days in a year

    $9.041

    the equation that satisfy this is

    V (t/365) = 30,000 (0.89) ^ (t/365).
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