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6 December, 23:55

Two long, parallel wires are separated by 2.0 m. Each wire has a 28-A current, but the currents are in opposite directions. Part A Determine the magnitude of the net magnetic field midway between the wires. Express your answer with the appropriate units. B

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  1. 7 December, 00:24
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    Given Information:

    Current = I = 28 A

    distance between wires = r = 2.0 m

    Required Information:

    Magnetic field = B = ?

    Answer:

    B = 12x10⁻⁶ T

    Step-by-step explanation:

    Biot-Savart Law is given by

    B = μ₀I/2πr

    Where μ₀ is the permeability of free space, I is the current flowing through the wire and B is the magnitude of the magnetic field produced.

    We are asked to find the magnetic field midway between the wires so r/2 = 1

    B = 4πx10⁻⁷*28/2π*1

    B = 6x10⁻⁶ T

    since the same amount of current flows in both wires therefore, equal amount of magnetic field will be produced in both wires

    B = 2*6x10⁻⁶ T

    B = 12x10⁻⁶ T

    Therefore, the net magnetic field midway between the two wires is 12x10⁻⁶ T.
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