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18 June, 04:03

The y component of the electric field of an electromagnetic wave traveling in the + x direction through vacuum obeys the equation Ey = (375 N/C) cos [kx - (2.20 * 1014 rad/s) t]. What is the wavelength of this electromagnetic wave?

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  1. 18 June, 04:14
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    Answer: 8.6 µm

    Explanation:

    At a long distance from the source, the components (the electric and magnetic fields) of the electromagnetic waves, behave like plane waves, so the equation for the y component of the electric field obeys an equation like this one:

    Ey = Emax cos (kx-ωt)

    So, we can write the following equality:

    ω = 2.2 1014 rad/sec

    The angular frequency and the linear frequency are related as follows:

    f = ω / 2π = 2.2 1014 / 2π (rad/sec) / rad = 0.35 1014 1/sec

    In an electromagnetic wave propagating through vacuum, the speed of the wave is just the speed of light, c.

    The wavelength, speed and frequency, are related by this equation:

    λ = c/f

    λ = 3.108 m/s / 0.35. 1014 1/s = 8.6 µm.
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