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9 June, 21:53

A 1200-kg car, initially moving at 20 m/s, comes to a stop at a red light over a time of 3 s from the moment the driver hit the brakes. What is the impulse delivered to the car by the static friction force (assumed constant) between the road and the tires

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  1. 9 June, 22:16
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    Mass of car (M) = 1200kg

    Initial velocity (u) = 20m/s

    Stop after time (t) = 3sec.

    Come to stop implies that the final velocity is zero, v=0m/s

    Using newton second law of motion

    F=m (v-u) / t

    Ft=m (v-u)

    Since impulse is Ft

    I=Ft

    Then, I=Ft=m (v-u)

    I=m (v-u)

    I=1200 (0-20)

    I=1200*-20

    I=-24,000Ns

    The impulse delivered to the car by static friction is - 24,000Ns
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