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30 August, 15:30

Jack pulls a sled across a level field by exerting a force of 110 n at an angle of 30 with the ground. what are the parallel and perpendicular components, respectively, of this force with respect to the ground?

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  1. 30 August, 15:47
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    You are given an applied force of 110 n with an angle of 30 ° with the ground. Since the force is not perpendicular or parallel to the sled then you will have two components. These components are in sine and cosine form.

    for parallel component

    x = rcos β

    x = 110cos30 °

    x = 95.26

    for the perpendicular component

    y = rsin β

    y = 110sin30 °

    y = 55
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