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24 October, 02:44

Superman can leap over tall buildings in a single bound. What does he do to the ground beneath him? Assume his mass is 100.0 ± 0.1 kg and his hips drop by 0.300 ± 0.020 m before he jumps. If he can jump over the top of PNC Plaza (tallest building in Raleigh), which is 164 ± 1 m, calculate the following with uncertainties:

a. Takeoff velocity

b. Acceleration just before takeoff

c. Force on ground at take off

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Answers (1)
  1. 24 October, 03:12
    0
    Height reached = 164m

    If velocity of launch be u

    u² = 2gh

    = 2 x 9.8 x 164

    = 3214.4

    u = 56.7 m / s

    difference in u = 1/2 (diff in h / h) x u

    1/2 x 1/164 x 56.7

    .17 or. 2

    u = 56.7 ±.2 m / s

    or 57± 1

    b) During the displacement of. 300 m, there is acceleration to achieve velocity of 56.7 m / s

    v² = 2as

    a = v² / 2s

    = 56.7² / (2 x. 3)

    = 5358.15 m / s²

    diff in a

    = 1/2 x (.02 /.3) x 5358.15

    178.6

    a = 5358.1 ±178.6

    c) force on the ground

    mass (g + a)

    = 100 x (9.8 + 5358.1)

    = 536790 N

    error in force = (.1/100 + 178.6 / 5358) x 536790

    = (.01 +.03) x 536790

    = 21471

    (536790 ± 21471) N
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