Ask Question
11 July, 05:55

A 65kg person throws a 0.045kg snowball forward with a ground speed of 30m/s. A second person, with a mass of 60kg, catches the snowball. Both people are on skates. The first person is initially moving forward with a speed of 2.5 m/s, and the second person is initially at rest. What are the velocities of the two people after the snowball is exchanged? Disregard friction between the skates and the ice.

+2
Answers (1)
  1. 11 July, 06:16
    0
    v₁ = 2.48m/s, v₂ = 0.02m/s

    Explanation:

    Momentum p must be conserved. p = mv

    1) First person throwing the snow ball. The momentum before the throw:

    p = (65kg + 0.045kg) * 2.5 m/s

    The momentum after the throw:

    p = 65kg * v₁ + 0.045kg * 30m/s

    Solving for the velocity v₁ of person 1:

    v₁ = ((65kg + 0.045kg) * 2.5 m/s - 0.045kg * 30m/s) / 65kg = 2.48m/s

    2) Second person catching the ball. The momentum before the catch:

    p = 0.045kg * 30m/s + 60kg * 0m/s

    The momentum after the catch:

    p = (60kg + 0.045kg) * v₂

    Solving for velocity v₂ of person 2:

    v₂ = 0.045kg * 30m/s / (60kg + 0.045kg) = 0.02 m/s
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “A 65kg person throws a 0.045kg snowball forward with a ground speed of 30m/s. A second person, with a mass of 60kg, catches the snowball. ...” in 📗 Physics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers