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2 November, 12:00

Hooke's law. The distance d when a spring is stretched by a hanging objective varies directly as the weight w of the object. If the distance is 38 cm when the weight is 3 kg, what is the distance when the weight is 7 kg? ... ?

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  1. 2 November, 12:20
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    Hooke's law is F=-kx, which means the elastic force contained by the spring is a product of the distance it stretches and its spring constant, but the direction of the force is opposite that of the displacement. We calculate as follows:

    (3 kg) (9.8 m/s^2) = - k (-0.38 m)

    k = 77.4

    Then use k to find the new displacement, again using Hooke's law:

    (7 kg) (9.8 m/s^2) = - (77.4) x

    x = - 0.89 m
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