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19 October, 16:49

A 1200 kg frictionless roller coaster starts from rest at a height of 19 m. What is its kinetic energy when it goes over hill that is 13 m high?

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  1. 19 October, 16:55
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    10.85 m/s

    Explanation:

    m = 1200 kg, h1 = 19 m, h2 = 13 m

    Let v be the velocity

    Use the conservation of energy

    Potential energy at 19 m = Potential energy at 13 m + kinetic energy

    m x g x h1 = m x g x h2 + 1/2 mv^2

    m x g (h1 - h2) = 0.5 x m v^2

    g (h1 - h2) = 0.5 v^2

    9.8 (19 - 13) = 0.5 x v^2

    v = 10.85 m/s
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