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5 March, 20:16

If a pendulum has a period of 4 seconds at the north pole with gravity force 9.83 ms^-2 and a 3.97m pendulum length, how could the same pendulum be adjusted to have the same period as the equator with 9.78ms^-2 gravity force?

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  1. 5 March, 20:32
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    The same pendulum could be adjusted to have the same period, in the equator must have a length of 3.949m.

    Explanation:

    Tnp = 4 sec

    gnp = 9.83 m/sec²

    Lnp = 3.97m

    Tequ = 4 sec

    gequ = 9.78 m/sec²

    Lequ=?

    Lequ = (Lnp * gequ) / gnp

    Lequ = 3.949 m
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