During a hard stop, a car and its passengers slow down with an acceleration of 8,0m/s^2. What magnitude force does a 50-kg passenger exert on the seat belt in such a stop?

F = 400 N

Explanation:

Given,

The acceleration of the car, a = 8 m/s²

The mass of the passenger, m = 50 Kg

The force acting on a body is equal to the product of the mass and its acceleration

F = m x a newtons

Substituting the given values in the above equation,

F = 50 Kg x 8 m/s²

= 400 N

Hence, the force exerted by the person on the seat belt is, F = 400 N