A 35 n object is on a 25 degree incline. the force of friction up the incline is 8.0 N.

-What is the acceleration of the block?

-What is the coefficient of kinetic friction?

The downwards component of weight of the object would be 35sin25 degrees = 14.8

F=14.8 - 8 = 6.8 N m = 35/9.8 = 3.57 kg

F=mA

Therefore,

3.57A = 6.8 N

=> A = 6.8/3.57

=> A = 1.902 ms^-2

F (max) = (U) R where (U) = coefficient of friction

and R = Normal reaction force

R = 35cos25

= 31.72 N

Since, F (max) = 8

8 = (U) * 31.72

=> (U) = 8/31.72

=> (U) = 0.25