A soccer ball is kicked horizontally off a bridge with a heigh of 36m. The ball travels 25m horizontally before it hits the pavement below. What was the soccer ball's speed when it was first kicked?

The initial velocity was U=22.14m/s

Explanation:

Step one:

Applying the third equation of motion

v² = u² + 2as

Where v = Final velocity

U = initial velocity

a = acceleration due to gravity

S = distance or displacement

Step two:

V = 0

a = 9.81m/s²

S=25m

U=?

Step three:

Substituting into the equation we have

0²=U²+2*9.81*25

0=U²+490.5

U²=-490.5

U=√490.5

U=22.14m/s