Ask Question
7 September, 17:58

A horizontal force of 20 newtons eastward causes a 10-kilogram box to have a displacement of 5 meters eastward. The total work done on the box by the 20-newton force is

(1) 40 J

(2) 100 J

(3) 200 J

(4) 1000 J

+4
Answers (2)
  1. 7 September, 18:06
    0
    The first thing you should remember is the definition of work

    W = F * d

    Where

    W: Work done.

    f: Force

    d: Distance.

    Substituting the values we have:

    W = (20) * (5) = 100Nm = 100J

    The answer is

    (2) 100J
  2. 7 September, 18:09
    0
    To get the total work, you will add the Applied work + frictional work.

    applied work = 20N x 5meter which is the displacement

    frictional work = Weight x displacement

    where the weight = mass x gravitational acceleration

    weight=10 kg x 9.8 m/s^2

    =98 kg m/s^2 or Newton

    work = N x m

    =98 N x 5 meters

    =490

    Total work = 490-450

    40 Joules

    answer is letter A.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “A horizontal force of 20 newtons eastward causes a 10-kilogram box to have a displacement of 5 meters eastward. The total work done on the ...” in 📗 Physics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers