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15 August, 12:27

In a fluorescent tube of diameter 3 cm, 3 times 1018 electrons and 0.75 times 1018 positive ions (with a charge of + e) flow through a cross-sectional area each second. What is the current in the tube?

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  1. 15 August, 12:29
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    current in the tube is 0.6A

    Explanation:

    Charged particles move in opposite directions, thus their contributions to total current are additive.

    I = (3 * 10¹⁸ + 0.75 * 10¹⁸) * (1.6 * 10⁻¹⁹)

    I = 0.6A
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