Ask Question
9 October, 02:04

A statue is to be 'scaled down.' It will have its size changed without changing its shape. It starts with an initial volume of 3.25 m3 and ends up with a final volume of 1.00 m3.

+3
Answers (1)
  1. 9 October, 02:06
    0
    The solution are in the explanation

    Explanation:

    Volume varies with the cube of the linear dimension

    Ratio of volumes is 3:1, therefore the ratio of the linear dimensions is 3^ (1/3) : 1 = 1.442:1

    Smaller statue is 350/1.442 cm = 242.7 cm

    C = pi*D, D is a linear dimension, so Ds = 50/1.442 = 34.67 cm

    Area varies with the square of the linear dimension; so the ratio of the areas will be (1/3) ^ (2/3) = 0.48; the surface area of the smaller statue will be 0.48 that of the original

    The mass of the model would vary directly with the volume, so the mass of the model will be 1/3 that of the original

    If the masses of the models are the same, then the model must be made of a material 3x the density of that used for the original.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “A statue is to be 'scaled down.' It will have its size changed without changing its shape. It starts with an initial volume of 3.25 m3 and ...” in 📗 Physics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers