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30 March, 14:08

An electron is to be accelerated from a velocity of 4.50*106 m/s to a velocity of 9.00*106 m/s. Through what potential difference must the electron pass to accomplish this?

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  1. 30 March, 14:11
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    -2.85 * 10^ (-17) J

    Explanation:

    Parameters given:

    Final velocity, v = 9 * 10^6 m/s

    Initial velocity, u = 4.5 * 10^6 m/s

    Using the conservation of energy formula, total energy is conserved:

    K. Ein + PEin = KEf + PEf

    K. Ef - K. Ein = P. Ein - P. Ef

    => - ∆P. E = K. Ef - K. Ein

    ∆P. E = K. Ein - K. Ef

    ∆P. E = ½mu² - ½mv²

    ∆P. E = ½m[ (4.5 * 10^6) ² - (9 * 10^6) ²]

    ∆P. E = ½ * 9.31 * 10^ (-31) * (-61.25 * 10¹²)

    ∆P. E = - 2.85 * 10^ (-17) J
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