A 1400 kg vehicle travelling at 22 m/s slows at a constant rate to 4.5 m/s in 6.75 s. What was the net force acting on the car during this time?

Net force = 3640 N

Explanation:

From first equation of motion

V = U + at

4.5 = 22 + 6.75a

(4.5-22) : 6.75 = a

acceleration (a) = - 2.6m/s^2 (negative sign shows deceleration, but actual acceleration is 2.6)

But Force = mass * acceleration

Force = 1400 * 2.6

Force = 3640 N