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25 January, 05:06

Three moles of ideal gas is inside a sealed rectangular container of size 0.2 m x 0.2 m x 0.4 m. If the pressure inside the container is 498,840 N/m^2, what is the temperature of the gas inside the container?

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  1. 25 January, 05:09
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    320 K

    Explanation:

    Given:

    Number of moles of gas, n = 3

    Dimensions of the rectangular container = 0.2 m * 0.2 m * 0.4 m

    Thus,

    Volume of the container = 0.2 m * 0.2 m * 0.4 m = 0.016 m³

    Pressure inside the container, P = 498,840 N/m²

    Now,

    From the ideal gas law, we have

    PV = nRT

    here,

    T is the temperature

    R is the ideal gas constant = 8.314 J / (mol·K)

    on substituting the values, we get

    498,840 * 0.016 = 3 * 8.314 * T

    or

    T = 320 K

    Hence, the pressure inside the container is 320 K
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