Ask Question
29 June, 14:10

A 27.5-g object moving to the right at 19.0 cm/s overtakes and collides elastically with a 11.5-g object moving in the same direction at 15.0 cm/s. Find the velocity of each object after the collision. (Take the positive direction to be to the right. Indicate the direction with the sign of your answer.)

27.5-g object cm/s?

11.5-g object cm/s?

+4
Answers (1)
  1. 29 June, 14:38
    0
    After collision, velocity of massive object 27.5 g has reduced from 19 cm/s to 16.64 cm/s while that of lighter object 11.5 has increased from 15 cm/s to 20.64 cm/s because of elastic collision.

    Explanation:

    As, this question has two parts: a) We have to find the velocity after the collision with the mass of the object 27.5 g.

    b) We have to find the velocity with 11.5 g mass of the object.

    Now,

    In this case the massive body collides with the lighter body. As we know;

    Mass of massive object = m1 = 27.5 g

    Velocity of m1 before collision = v1 = 19 cm/s

    mass of lighter object = m2 = 11.5 g

    velocity of m2 before collision = v2 = 15 cm/s

    We have to find the velocity of m1 and m2 after the collision

    a)

    Velocity of 27.5 g object after collision = v1' = ?

    v1' = (m1-m2) / (m1+m2) * v1 + 2*m2 / (m1+m2) * v2

    v1' = (27.5-11.5) / 27.5+11.5) * (19) + 2 * (11.5) / (27.5+11.5) * (15)

    v1' = 7.795 + 8.846

    v1' = 16.64 cm/s.

    b)

    Velocity of 11.5 g object after collision = v2' = ?

    v2' = 2*m1 / (m1+m2) * v1 + (m2-m1) / (m1+m2) * v2

    v2' = 2 * (27.5) / (27.5+11.5) * (19) + (11.5-27.5) / (27.5+11.5) * (15)

    v2' = 26.795 + (-6.154)

    v2' = 20.641 cm/s.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “A 27.5-g object moving to the right at 19.0 cm/s overtakes and collides elastically with a 11.5-g object moving in the same direction at ...” in 📗 Physics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers