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13 December, 07:43

There is a bus moving at 30.2 m/s and the bus must now jump a 50 foot gap in the freeway. if the interchange has a 5° incline how far can the bus travel and still land on the same vertical level after leaves the ramp? will the bus make it the 50 feet?

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  1. 13 December, 08:01
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    The bus won’t make it by a long shot if I did the math right.

    I split the velocity into two components: vertical and horizontal, using trig. I then used a modified height formula to get that 2.63t-4.9t^2 = 0, t = 0.531639, x = 30.08*0.531639 = 16.16 meters before it falls into the ditch. Note that 2.63 = 30.2*sin (5) and 30.08 = 30.2*sin (5). I hope that made some sense!
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