The diagram shows a 15-kg box resting on a wedge which has an angle of inclination of 30° and a coefficient of friction of 0.15. Find the value of the vector Fg.

Question

Layne Trujillo

Physics

12 October, 08:42

The diagram shows a 15-kg box resting on a wedge which has an angle of inclination of 30° and a coefficient of friction of 0.15. Find the value of the vector Fg.

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Answers (2)

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Lily Yoder · Answer 1

We calculate first for the normal force, Fn, which is equal to the product of the force and the cosine of the given angle,

Fn = (15 kg) (9.8 m/s²) (cos 30°)

Fn = 127.30 N

Then, to calculate for the Fg, we multiply the normal force by the given coefficient.

Fg = (127.30 N) (0.15) = 19 N

The nearest value is letter A.

Mccullough · Answer 2

The correct answer is B. 147.15 N