A particle of mass 6.7*10^-6 kg and charge 13 μC is moving at a speed of 70 m/s perpendicularly to a uniform 9.4-T magnetic field. What is the radius of the particle's circular path?

Question

Nikita

Physics

15 September, 18:23

A particle of mass 6.7*10^-6 kg and charge 13 μC is moving at a speed of 70 m/s perpendicularly to a uniform 9.4-T magnetic field. What is the radius of the particle's circular path?

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Answers (1)

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Sariah Hammond · Answer 1

3.8379 meters

Explanation:

A charged particle into an uniform magnetic field describes a circular movement with radius "r" acording to the equation r = (m*v) / (q*B), where m is the mass of the particle, v its velocity, q the charge, and B the perpendicularly uniform magnetic field. Replacing your value on this equation, the radius is 3.8379 m. I suggest to verify the value of the magnetic field, because 9.4 is a extremely high magentic field.