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4 March, 18:39

The average intensity of sunlight at the top of the earth's atmosphere in 1390 w/m2. what is the maximum energy that a 34-m x 46-m solar panel could collect in 2.0 hours in this sunlight

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  1. 4 March, 18:42
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    Panel surface area = 34m*46m=1,564m^2

    total power = 1564m^2*1390w/m^2

    =2173960watts

    now you must calculate total energy.

    Energy = power*Time

    However time must be in seconds so we multiply 2hrs*60min*60s=7200seconds

    7200s*2173960w = 15,652,512,000 joules of energy
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