A 70kh man jumping from a window lands in an elevated

firerescue net 11.0 m below the window. He momentarily stops when

hehas stretched the net by 1.50 m. Assuming that mechanicalenergy

is conserved during this process and the net functions likean ideal

spring, find the leastic potential energy of the net whenit is

stretched by 1.50 m.

potential energy of net is 8.58 kJ

Explanation:

given data

mass m = 70 kg

height h = 11 m

stop distance x = 1.50 m

to find out

potential energy of net

solution

we know here man eventually stop

so elastic potential energy of net = change in potential energy of man body

so equation will be

potential energy of net = m*g*h ... 1

here m is mass and h is total height = (h + x)

height = 11 + 1.5 = 12.5 m and g is 9.8

so put here value in equation 1

potential energy of net = m*g*h

potential energy of net = 70*9.8*12.5

potential energy of net = 8575 J

so potential energy of net is 8.58 kJ