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2 February, 17:19

In physics how much energy is required to raise the temp of 9.78kg of water from 40.82c to 52.07c? The specific heat of water in this state is 4186j/kg-c.

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Answers (2)
  1. 2 February, 17:35
    0
    the amount of energy required to raise the temperature of the water is 460564.65 J

    Explanation:

    The energy required to raise the temperature of water can be calculated as follows;

    Q = mcΔθ

    where;

    Q is the quantity of heat or energy required to raise the temperature of water

    m is mass of water

    c is specific heat capacity of water

    Δθ is change in temperature = T₂ - T₁

    Given;

    m = 9.78kg

    c = 4186j/kg-c

    Δθ = T₂ - T₁ = 52.07°C - 40.82°C = 11.25°C

    Q = mcΔθ

    Q = (9.78) (4186) (11.25)

    Q = 460564.65 J

    Therefore, the amount of energy required to raise the temperature of the water is 460564.65 J
  2. 2 February, 17:40
    0
    469.6KJ

    Explanation:

    Heat energy required can be calculated using the formula

    H = mc∆t where

    m is the mass of the water

    c is the specific heat capacity of the water

    ∆t is the change in temperature of the water

    Given m = 9.78kg

    c = 4186j/kg-c.

    ∆t = 52.07°C - 40.82°C

    ∆t = 11.25°C

    H = 9.78 * 4186 * 11.25

    H = 460,564.65Joules

    = 460.6KJ
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