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22 May, 08:17

A 2 kg soccer ball is traveling 28.62m/s when it hits the wall and bounces off of the wall with a velocity of 20 m/s. If the wall exerted an average force of 652.36N on the ball, how long was the ball in contact with the wall?

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  1. 22 May, 08:29
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    0.149 s or 0.15 s

    Explanation:

    let initially ball is moving towards left hence initial velocity = - 28.62 m/s

    final velocity as ball moves right = + 20 m/s

    force = rate of change in momentum

    force = mass * change in velocity / time

    or time = mass * change in velocity / force

    time = 2 * (20 - (-28.62)) / 652.36

    time = 2 * (20 + 28.62)) / 652.36

    time = 2 * 48.62/652.36

    time = 0.149 s or 0.15 s
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