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6 April, 11:37

A car is traveling at a constant speed on the highway. Its tires have a diameter of 61.0 cm and are rolling without sliding or slipping. If the angular speed of the tires is 50.0 rad/s, what is the speed of the car

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Answers (2)
  1. 6 April, 11:44
    0
    15.25 m/s

    Explanation:

    Speed: This can be defined as the rate of change of distance. The S. I unit of speed is m/s.

    The expression of speed in terms of angular speed is given as

    v = rω ... Equation 1

    Where v = speed of the car, ω = angular speed of the tires, r = radius of the tires

    Given: ω = 50 rad/s, r = d/2 = where d = diameter of the tire, d = 61 cm

    r = 61/2 = 30.5 cm = 0.305 m.

    Substitute into equation 1

    v = 50 (0.305)

    v = 15.25 m/s.

    Hence the speed of the car = 15.25 m/s
  2. 6 April, 11:53
    0
    15.25 m/s

    Explanation:

    Velocity is given as;

    v = angular velocity x radius

    v = ωr

    where;

    v is velocity, ω = angular velocity and r is radius)

    We are given;

    ω = 50 rad/s

    diameter = 61cm

    So, radius = 61/2 = 30.5 cm = 0.305m

    Plugging in the relevant values to get;

    v = 50 x 0.305

    v = 15.25 m/s

    Therefore the car is travelling at a constant speed of 15.25 m/s
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