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13 February, 08:34

A piece of bismuth with a mass of 4.06 g 4.06 g gains 423 J 423 J of heat. If the specific heat of bismuth is 0.123 J / (g ° C) 0.123 J / (g°C), what is the change in temperature of the sample?

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  1. 13 February, 08:43
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    Answer: 846°C

    Explanation:

    The quantity of Heat Energy (Q) required to heat bismuth depends on its Mass (M), specific heat capacity (C) and change in temperature (Φ)

    Thus, Q = MCΦ

    Given that:

    Q = 423 joules

    Mass of bismuth = 4.06g

    C = 0.123 J / (g°C)

    Φ = ?

    Then, Q = MCΦ

    423 J = 4.06g x 0.123 J / (g°C) x Φ

    423 J = 0.5J/°C x Φ

    Φ = (423J / 0.5g°C)

    Φ = 846°C

    Thus, the change in temperature of the sample is 846°C
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