4. Three people are pushing a 500 kg of box in the same direction. Applied forces are 30 N, 20 N, and 10 N respectively. If the acceleration of the box is 0.02 m/s2, what is the magnitude of a force created by friction?

Question

Angelique Todd

Physics

12 June, 16:04

4. Three people are pushing a 500 kg of box in the same direction. Applied forces are 30 N, 20 N, and 10 N respectively. If the acceleration of the box is 0.02 m/s2, what is the magnitude of a force created by friction?

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Answers (1)

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Stephen Snow · Answer 1

Answer:50N

Explanation:

mass=500kg

Total force=30+20+10=60N

Acceleration=0.02m/s^2

Resultant force=mass x acceleration

Resultant force=500 x 0.02

Resultant force=10N

Frictional force=total force - resultant force

Frictional force=60-10=50N