A 96.1 kg man sits on the stern of a 6 m long boat. The prow of the boat touches the pier, but the boat isn't tied. The man notices his mistake, stands up and walks to the boat's prow, but by the time he reaches the prow, it's moved 3.66 m away from the pier. Assuming no water resistance to the boat's motion, calculate the boat's mass (not counting the man). Answer in units of kg.

Question

Clayton Romero

Physics

15 May, 17:45

A 96.1 kg man sits on the stern of a 6 m long boat. The prow of the boat touches the pier, but the boat isn't tied. The man notices his mistake, stands up and walks to the boat's prow, but by the time he reaches the prow, it's moved 3.66 m away from the pier. Assuming no water resistance to the boat's motion, calculate the boat's mass (not counting the man). Answer in units of kg.

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Answers (1)

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Alana Bradley · Answer 1

Answer: M = 154.721kg

Explanation:

Given parameter

M1 = 96.1Kg

Length of the boat (L1) = 6m

L = 6 + 3.66 (3.66 meter away from pair) = 9.66m

M1:L1 = 96.1:6. X:9.66

(96.1/6) = X/9.66

By cross multiplying

96.1*9.66 = 6X

X = 928.326/6

X = M = 154.721kg