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25 December, 12:25

When tuning his guitar, a music student notices that the string is not vibrating at the desired frequency of 120 Hz, so he tightens the string by 15.5% to get this frequency. At what frequency was the string vibrating when he first started the tuning process

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  1. 25 December, 12:45
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    We know that

    frequency ∝ √ Tension

    So

    Δn / n = 1/2 (ΔT / T)

    Δn / n =.155 / 2 (GIVEN)

    =.0775

    Δn =.0775 n

    Let the original frequency be n

    n + Δn = 120

    n +.0775 n = 120

    n = 111.36
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