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5 March, 08:45

How many ml of (g measured at stp are produced at a platinum cathode in the electrolysis of s (aq by 4.35 a of electric current in 6.00 min?

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  1. 5 March, 09:00
    0
    We are given with

    I = 4.35 A

    t = 6 min or 360 s

    Cathode - Platinum (MW = 195)

    Assuming the gas produced is H2 (MW = 2)

    The formula is

    V = 22.414 x I x t/9500

    V = 22.414 (4.35) (360) / 96500

    V = 0.364 L or 364 mL
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