A delivery man starts at the post office, drives 40 km north, then 20 km west, then 60 km northeast, and finally 50 km north to stop for lunch. use a graphical method to find his net displacement vector.

assuming north-south along the Y-axis and east-west along the X-axis

X = total X-displacement

from the graph, total displacement along X-direction is given as

X = 0 - 20 + 60 Cos45 + 0

X = 42.42 - 20

X = 22.42 m

Y = total Y - displacement

from the graph, total displacement along Y-direction is given as

Y = 40 + 0 + 60 Sin45 + 50

Y = 90 + 42.42

Y = 132.42 m

magnitude of the net displacement vector using Pythagorean theorem is given as

magnitude : Sqrt (X² + Y²) = Sqrt (22.42² + 132.42²) = 134.31 m

Direction : tan⁻¹ (Y/X) = tan⁻¹ (132.42/22.42) = 80.4 deg north of east