At the 18th green of the U. S. Open you need to make a 23.5ft putt to win the tournament. When you hit the ball, giving it an initial speed of 1.45 m/s, it stops 5.10 ft short of the hole. Assuming the deceleration caused by the grass is constant, what should the initial speed have been to just make the putt? 2. What initial speed do you need to make the remaining 5.10 ft putt?

Question

David Garza

Physics

24 March, 03:41

At the 18th green of the U. S. Open you need to make a 23.5ft putt to win the tournament. When you hit the ball, giving it an initial speed of 1.45 m/s, it stops 5.10 ft short of the hole. Assuming the deceleration caused by the grass is constant, what should the initial speed have been to just make the putt? 2. What initial speed do you need to make the remaining 5.10 ft putt?

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Answers (1)

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Marcus Blanchard · Answer 1

1.63 m/s

Explanation:

a = acceleration of the ball

d = stopping distance = 23.5 - 5.10 = 18.4 ft = 5.61 m

v₀ = initial velocity of the car = 1.45 m/s

v = final velocity of the car = 0 m/s

Using the equation

v² = v₀² + 2 a d

0² = 1.45² + 2 a (5.61)

a = - 0.187 m/s²

To win the tournament:

a = acceleration of the ball = - 0.187 m/s²

d = stopping distance = 23.5 ft = 7.1 m

v₀ = initial velocity of the car = ?

v = final velocity of the car = 0 m/s

Using the equation

v² = v₀² + 2 a d

0² = v₀² + 2 ( - 0.187) (7.1)

v₀ = 1.63 m/s