A simple pendulum is 5.00 m long. what is the period of small oscillations for this pendulum if it is located in an elevator (a) accelerating upward at 5.00 m/s2? (b) accelerating downward at 5.00 m/s2? (c) what is the period of this pendulum if it is placed in a truck that is accelerating horizontally at 5.00 m/s2

Question

Yadira Howe

Physics

15 May, 03:48

A simple pendulum is 5.00 m long. what is the period of small oscillations for this pendulum if it is located in an elevator (a) accelerating upward at 5.00 m/s2? (b) accelerating downward at 5.00 m/s2? (c) what is the period of this pendulum if it is placed in a truck that is accelerating horizontally at 5.00 m/s2

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Answers (1)

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Malia · Answer 1

Pendulum period in seconds T ≈ 2π√ (L/G) L is length of pendulum in meters G is gravitational acceleration = 9.8 m/s²

So the answers are the following:

a) use G = 9.8 + 5.0 = 14.8 m/s²b) use G = 9.8 - 5.0 = 4.8 m/s² c) 2π√ (L/G) = 2pi √5/9.8 = 4.49 m/s^2