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14 March, 08:15

6. A train starts from rest and accelerates uniformly until it has traveled 5.6 km and acquired a velocity of 42m/s What is the approximate acceleration of the train during this time?

0.17 m/s2

0.20 m/s2

0.16 m/s2

0.14 m/s2

0.19 m/s2

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Answers (2)
  1. 14 March, 08:20
    0
    Answer;

    0.16 m/s²

    Explanation;

    From one of the equation of linear motion;

    vf2 - vi2 = 2ax

    Where;

    vf = final speed after traveling a distance x at constant acceleration; vf = 42 m/s

    vi = initial speed = 0 (starts from rest)

    a = constant acceleration while traveling a distance x

    x = distance traveled at constant acceleration; x = 5.6 km = 5600 m

    Therefore;

    a = vf2 / (2x)

    = 422 / (2*5600) m/s²

    = 0.1575 m/s²

    ≅ 0.16 m/s²
  2. 14 March, 08:38
    0
    O. 16 m/s2
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