If a rock weighing 2,200 N is dropped from a height of 15 m, what is its KE just before it hits the ground? Remember, weight is measured in newtons (N), and is equal to mass times gravity.

A. 0 J

B. 2,224 J

C. 147 J

D. 33,000 J

Question

Valinto

Physics

26 January, 19:52

If a rock weighing 2,200 N is dropped from a height of 15 m, what is its KE just before it hits the ground? Remember, weight is measured in newtons (N), and is equal to mass times gravity.

A. 0 J

B. 2,224 J

C. 147 J

D. 33,000 J

+3

Answers (1)

Know the Answer?

Giovanny Spears · Answer 1

This is a question conservation of energy. That is;

Potential energy = Kinetic energy

mgh = 1/2*mv^2 = KE

Therefore,

KE = mgh = (2200/9.81) * 9.81*15 = 2200*15 = 33000 J

The correct answer is D.

If a rock weighing 2,200 N is dropped from a height of 15 m, what is its KE just before it hits the ground? Remember, weight is measured in newtons (N), and is equal to mass times gravity.A. 0 JB. 2,224 JC. 147 JD. 33,000 J

If a rock weighing 2,200 N is dropped from a height of 15 m, what is its KE just before it hits the ground? Remember, weight is measured in newtons (N), and is equal to mass times gravity.

A. 0 J

B. 2,224 J

C. 147 J

D. 33,000 J