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26 September, 08:43

V=vi+at^2 dimensional correct

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  1. 26 September, 08:52
    Yes, dimensionally the equation is correct.


    This equation is the kinematic equation for uniformly accelerated motion, then we study the units of each member to conclude whether it is dimensionally correct.

    vi = initial velocity [m/s]

    a = acceleration [m/s^2]

    t = time [s]

    v = final velocity

    therefore we have:

    [m/s] + [m/s^2]*[t^2], the second term now is m/s

    [m/s] + [m/s] = [m/s]

    So the analysis is correct.
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