1.80 kJ of heat is added to a slug of gold and a separate 1.80 kJ of heat is added to a slug of manganese. The heat capacity of the gold slug is 149J/°C while the heat capacity of the manganese slug is 505 J/°C. If the slugs are each originally at 25.00°C, what is the final temperature of each slug?

Question

Yair Young

Physics

29 November, 14:13

1.80 kJ of heat is added to a slug of gold and a separate 1.80 kJ of heat is added to a slug of manganese. The heat capacity of the gold slug is 149J/°C while the heat capacity of the manganese slug is 505 J/°C. If the slugs are each originally at 25.00°C, what is the final temperature of each slug?

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Answers (1)

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Kaiden Mercado · Answer 1

final temperature of slug of gold is 37°C

final temperature of slug of manganese is 28.56°C

Explanation:

Hello! To solve this problem we must take into account the concept of heat capacity, this is defined as the ratio between energy and temperature rise.

In other words it is the amount of energy that is required to increase a temperature degree.

Taking into account the above we infer the following equation

where

C=heat capacity